(************** Content-type: application/mathematica ************** Mathematica-Compatible Notebook This notebook can be used with any Mathematica-compatible application, such as Mathematica, MathReader or Publicon. The data for the notebook starts with the line containing stars above. To get the notebook into a Mathematica-compatible application, do one of the following: * Save the data starting with the line of stars above into a file with a name ending in .nb, then open the file inside the application; * Copy the data starting with the line of stars above to the clipboard, then use the Paste menu command inside the application. Data for notebooks contains only printable 7-bit ASCII and can be sent directly in email or through ftp in text mode. Newlines can be CR, LF or CRLF (Unix, Macintosh or MS-DOS style). 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For more information on notebooks and Mathematica-compatible applications, contact Wolfram Research: web: http://www.wolfram.com email: info@wolfram.com phone: +1-217-398-0700 (U.S.) Notebook reader applications are available free of charge from Wolfram Research. *******************************************************************) (*CacheID: 232*) (*NotebookFileLineBreakTest NotebookFileLineBreakTest*) (*NotebookOptionsPosition[ 24991, 940]*) (*NotebookOutlinePosition[ 26366, 982]*) (* CellTagsIndexPosition[ 26322, 978]*) (*WindowFrame->Normal*) Notebook[{ Cell[TextData[{ StyleBox["MATH 257 Calculus III\t\t\t\t\t\t\t\tWeek of April 7, 2003", FontSize->14], "\n", StyleBox["Lab 2: Serious Series", "Title"], "\n", StyleBox["Name 1\nName 2\nSection:", "Section"] }], "Text"], Cell["\<\ I. Laboratory Objectives \tto get down with series, geometric series, \tand the integral test\ \>", "Text", FontSize->14], Cell[TextData[{ "II. Formatting and Syntax Information:\n\tUse the Basic Input Palette to \ find ", StyleBox[" \n\t", "Section"], Cell[BoxData[ \(TraditionalForm\`\[Sum]\+\(n = 1\)\%\[Infinity] a\_n\)], FontSize->18], StyleBox[" and ", FontSize->18], Cell[BoxData[ \(TraditionalForm\`\[Integral]\_a\%b f[x] \[DifferentialD]x\)], FontSize->18] }], "Text", FontSize->14], Cell[TextData[StyleBox["Infinite Series", FontSize->20]], "Title", Evaluatable->False, AspectRatioFixed->False, FontColor->RGBColor[1, 0, 0]], Cell[TextData[{ "An infinite series is an infinite sum. \nIn the", StyleBox[" ", FontColor->RGBColor[1, 0, 0]], StyleBox["infinite sequence", FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], ", {", Cell[BoxData[ \(TraditionalForm\`a\_n\)]], "} represents an infinite list of values:\n\t{", Cell[BoxData[ \(TraditionalForm\`\(a\_1, \ a\_2, \ a\_3, \ \(.\ .\ .\)\ }\)\)]], "\nIn an ", StyleBox["infinite series", FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], ", ", Cell[BoxData[ \(TraditionalForm\`\[Sum]\+\(n = 1\)\%\[Infinity] a\_n\)]], " represents an infinite sum:\n\t", Cell[BoxData[ \(TraditionalForm\`a\_1 + a\_2 + a\_3 + \(.\ .\ .\)\)]], "\n\t\nSummations can be finite or infinite. Let's start with a finite \ sum. The sum below has ten terms being added. Execute the statement below:\t\ " }], "Text"], Cell[BoxData[ \(\[Sum]\+\(n = 1\)\%10\( 5 - n\)\/\(3 n\^5\)\)], "Input", FontSize->14], Cell[TextData[{ "To find the decimal approximation of this fraction to 20 significant \ digits, use the ", StyleBox["Mathematica", FontSlant->"Italic"], " command below. The syntax is ", StyleBox["N", FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], StyleBox[" for numeric value", FontWeight->"Bold"], ", the ", StyleBox["%", FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], StyleBox[" sign refers to the previous computation", FontWeight->"Bold"], " and ", StyleBox["20", FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], StyleBox[" is the number of significant digits", FontWeight->"Bold"], " you desire when computing the numeric value." }], "Text"], Cell[BoxData[ \(N[%, 20]\)], "Input", FontSize->14], Cell[TextData[{ "What you have now calculated is the 10th partial sum or ", Cell[BoxData[ \(TraditionalForm\`S\_10\)]], "of the infinite series ", Cell[BoxData[ \(\[Sum]\+\(n = 1\)\%\[Infinity]\( 5 - n\)\/\(3 n\^5\)\)]], ". Suppose you wanted the sum of the first 150 terms of this infinite \ series:" }], "Text"], Cell[BoxData[ \(\[Sum]\+\(n = 1\)\%150\( 5 - n\)\/\(3 n\^5\)\)], "Input", FontSize->14], Cell[TextData[{ "This huge fraction is hard to read and even harder to estimate, so let's \ once again ask ", StyleBox["Mathematica", FontSlant->"Italic"], " for a decimal approximation:" }], "Text"], Cell[BoxData[ \(N[%, 20]\)], "Input", FontSize->14], Cell[TextData[{ "It seems that our series is converging. ", StyleBox["Mathematica", FontSlant->"Italic"], " can check this for us." }], "Text"], Cell[BoxData[ \(\[Sum]\+\(n = 1\)\%\[Infinity]\( 5 - n\)\/\(3 n\^5\)\)], "Input", FontSize->14], Cell["\<\ This is not much help unless you are familiar with the Zeta \ function. Let's ask for a decimal approximation:\ \>", "Text"], Cell[BoxData[ \(N[%, 20]\)], "Input", FontSize->14], Cell[TextData[{ "\nAnother way to see what is going on would be to make a ", StyleBox["ListPlot", "Input"], " of the ", StyleBox["sequence of partial sums", FontWeight->"Bold"], " ", StyleBox["S[n]", "Input"], ". The following will do this:" }], "Text"], Cell[BoxData[ \(\(\(\[IndentingNewLine]\)\(S[ n_] := \[Sum]\+\(k = 1\)\%n\( 5 - k\)\/\(3 k\^5\)\)\)\)], "Input"], Cell[TextData[{ "\nSee how we had to use k instead of n there? That's because we wanted \ the sum to go ", StyleBox["from 1 to n", FontWeight->"Bold"], ", so we needed a second variable to keep track of this. Now we can ", StyleBox["ListPlot", "Input"], " it using the ", StyleBox["Table", "Input"], " command. Let's plot it for n=1 to 100:" }], "Text"], Cell[BoxData[ \(\(\(\[IndentingNewLine]\)\(ListPlot[ Table[{n, S[n]}, {n, 1, 100}]]\)\)\)], "Input"], Cell[TextData[StyleBox["Geometric Series", FontSize->20]], "Title", Evaluatable->False, AspectRatioFixed->False, FontColor->RGBColor[1, 0, 0]], Cell[TextData[{ "Geometric Series are a specific type of infinite series. Geometric Series \ have the form:\n\n\t", StyleBox["a + ar + ", FontWeight->"Bold"], Cell[BoxData[ \(TraditionalForm\`ar\^2\ + \ ar\^3\ + \ ar\^\(\(4\)\(\ \)\) + \ \(\(.\)\(\ \)\(.\)\(\ \)\(.\)\)\ \ = \ \ \[Sum]\+\(n = 1\)\%\[Infinity] ar\^\(n - 1\)\)], FontWeight->"Bold"], "\n\n\t", StyleBox["a", FontColor->RGBColor[1, 0, 0]], " is the first term of the series and can be any real number\n\t", StyleBox["r", FontColor->RGBColor[1, 0, 0]], " is the ratio of adjacent terms. It can also be any real number. " }], "Text"], Cell[TextData[{ StyleBox["\n", FontSize->20], StyleBox["When | r | < 1, the Geometric Series converges, but\nwhen | r | \ \[GreaterEqual] 1, the Geometric Series diverges.\nThe sum of a convergent \ Geometric Series is ", FontSize->18], Cell[BoxData[ \(TraditionalForm\`a\/\(1 - r\)\)], FontSize->24] }], "Title", Evaluatable->False, AspectRatioFixed->False, FontColor->RGBColor[0, 0, 1]], Cell[BoxData[{ RowBox[{ RowBox[{ StyleBox[\(Let'\), "Section", FontSize->18], StyleBox["s", "Section", FontSize->18], StyleBox[" ", "Section", FontSize->18], StyleBox["look", "Section", FontSize->18], StyleBox[" ", "Section", FontSize->18], StyleBox["at", "Section", FontSize->18], StyleBox[" ", "Section", FontSize->18], StyleBox["a", "Section", FontSize->18], StyleBox[" ", "Section", FontSize->18], StyleBox["few", "Section", FontSize->18], StyleBox[" ", "Section", FontSize->18], RowBox[{ StyleBox["examples", "Section", FontSize->18], StyleBox[":", "Section", FontSize->18], "\[IndentingNewLine]", StyleBox[ RowBox[{"The", " ", "series", " ", RowBox[{\(\[Sum]\+\(n = 1\)\%\[Infinity]\), StyleBox[\(4 \((3\/5)\)\^\(n - 1\)\), "Subsection", FontSize->14]}]}], FontFamily->"Times"]}]}], StyleBox[" ", "Subsection", FontFamily->"Times", FontSize->14]}], "\n", StyleBox[\(has\ a\ = \ \(4\ and\ r\ = \ 3/5. \ Since\ | r\ | \ \(\(<\)\(\ \)\(1\)\)\), \ this\ series\ will\ converge . \nLet' s\ look\ at\ the\ nth\ partial\ sums . \ \ First, \ define\ the\ sequence\ of\ partial\ sums, \ and\ then\ evaluate\ \(\(it\)\(:\)\)\), FontFamily->"Times"]}], "Text", FontSize->14], Cell[BoxData[ RowBox[{\(S[n_]\), ":=", " ", RowBox[{\(\[Sum]\+\(k = 1\)\%n\), StyleBox[\(4 \((3\/5)\)\^\(k - 1\)\), "Subsection", FontSize->14]}]}]], "Input", FontSize->12], Cell[BoxData[ \(S[1]\)], "Input", FontSize->14], Cell[BoxData[ \(\(\(\[IndentingNewLine]\)\(S[2]\)\)\)], "Input"], Cell[BoxData[ \(N[%]\)], "Input"], Cell[BoxData[ \(S[5]\)], "Input"], Cell[BoxData[ \(N[%]\)], "Input"], Cell[BoxData[ \(S[10]\)], "Input"], Cell[BoxData[ \(N[%]\)], "Input"], Cell["\<\ Try getting this next one as a decimal to 20 significant digits:\ \>", "Text"], Cell[BoxData[ \(S[50]\)], "Input"], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[BoxData[ \(S[100]\)], "Input"], Cell[BoxData[ \(N[%, 30]\)], "Input"], Cell[BoxData[ \(S[n]\)], "Input"], Cell[TextData[StyleBox["To find the limit of the nth partial sum:", FontWeight->"Bold"]], "Text", FontFamily->"Helvetica", FontSize->14], Cell[BoxData[ \(\(\(\[IndentingNewLine]\)\(Limit[S[n], \ n \[Rule] \ \[Infinity]]\)\)\)], "Input"], Cell[TextData[{ StyleBox["Of course, we could have asked ", "Section"], StyleBox["Mathematica", "Section", FontSlant->"Italic"], StyleBox[" to compute this infinite sum directly:", "Section"] }], "Text", FontSize->14, FontWeight->"Bold"], Cell[BoxData[ RowBox[{" ", RowBox[{\(\[Sum]\+\(n = 1\)\%\[Infinity]\), StyleBox[\(4 \((3\/5)\)\^\(n - 1\)\), "Subsection", FontSize->14]}]}]], "Input"], Cell[TextData[{ StyleBox["The Integral Test on ", FontSize->20], StyleBox["Mathematica", FontSize->20, FontSlant->"Italic"], StyleBox[" ", FontSize->20] }], "Title", Evaluatable->False, AspectRatioFixed->False, FontColor->RGBColor[1, 0, 0]], Cell[TextData[{ "Many infinite series are not geometric, and so a large portion of this \ course is spent developing tests for infinite series which tell us if the \ series converges or diverges. When geometric series converge, we can always \ find the sum of the series: S = ", Cell[BoxData[ \(TraditionalForm\`a\/\(1 - r\)\)]], ". For most series, however, we will only be able to tell if the series \ converges or diverges . . finding the sum of the series is often just too \ difficult by hand.\n\nIntegral Test:\nIf f(x) is a continuous, positive and \ decreasing function on [1, \[Infinity]) and \n", Cell[BoxData[ \(TraditionalForm\`a\_n\)]], "= f(n) for each term in the positive termed series ", Cell[BoxData[ \(TraditionalForm\`\[Sum]\+\(n = 1\)\%\[Infinity] a\_n\)]], ",\nthen ", Cell[BoxData[ \(TraditionalForm\`\[Sum]\+\(n = 1\)\%\[Infinity] a\_n\)]], " converges if and only if ", Cell[BoxData[ \(TraditionalForm \`\(\[Integral]\_1\%\[Infinity]\( f(x)\) \[DifferentialD]x\ \)\)]], "converges.\n\nLook at the example ", Cell[BoxData[ \(TraditionalForm\`\[Sum]\+\(n = 1\)\%\[Infinity] 1\/n\^2\)]], ". \nFirst check that the corresponding function f(x) = ", Cell[BoxData[ \(TraditionalForm\`1\/x\^2\)]], "is continuous, positive and decreasing on [1,\[Infinity]) by graphing \ f(x)." }], "Text"], Cell[BoxData[ \(Plot[1\/x\^2, \ {x, 0, 20}]\)], "Input"], Cell["\<\ Then check if the integral from 1 to \[Infinity] converges or \ not:\ \>", "Text"], Cell[BoxData[ \(\(\(\[IndentingNewLine]\)\(\[Integral]\_1\%\[Infinity]\( 1\/x\^2\) \[DifferentialD]x\)\)\)], "Input"], Cell[TextData[{ "Since the improper integral ", Cell[BoxData[ \(TraditionalForm\`\[Integral]\_1\%\[Infinity]\( 1\/x\^2\) \[DifferentialD]x\)]], " is convergent, the infinite series \n", Cell[BoxData[ \(TraditionalForm\`\[Sum]\+\(n = 1\)\%\[Infinity] 1\/n\^2\)]], "is also convergent.\n\n", StyleBox["Mathematica", FontSlant->"Italic"], " can actually compute the sum of the series:" }], "Text"], Cell[BoxData[ \(\[Sum]\+\(n = 1\)\%\[Infinity] 1\/n\^2\)], "Input"], Cell[TextData[{ "Problems \nThis is the part of the lab you will hand in for the lab. ", StyleBox["Delete all the above stuff (except the title, your name, and \ section) before you submit your lab in Blackboard.", FontColor->RGBColor[0, 0, 1]], " " }], "Subtitle", FontSize->24], Cell[TextData[{ StyleBox["1. Given the series ", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[Sum]\+\(n = 1\)\%\[Infinity] 6 \((5\^\(-n\))\)\)], FontColor->RGBColor[1, 0, 0]], StyleBox[":", FontColor->RGBColor[1, 0, 0]] }], "Text", FontSize->18], Cell[TextData[{ "\ta.) Find the 5th partial sum, ", Cell[BoxData[ \(TraditionalForm\`S\_5\)]], " and its decimal approximation." }], "Text", FontSize->14, FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\tb.) Find the 10th partial sum, ", Cell[BoxData[ \(TraditionalForm\`S\_10\)]], " and its decimal approximation to 10 significant digits." }], "Text", FontSize->14, FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\tc. ) Find the 20th partial sum, ", Cell[BoxData[ \(TraditionalForm\`S\_20\)]], " and its decimal approximation to 20 significant digits" }], "Text", FontSize->14, FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell["\td.) What is the sum of the infinite series ?", "Text", FontSize->14, FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\te.) Identify ", StyleBox["a", FontSlant->"Italic"], " and ", StyleBox["r", FontSlant->"Italic"], " for this series and compare the answer ", StyleBox["Mathematica", FontSlant->"Italic"], " just gave you with the computation of ", Cell[BoxData[ \(TraditionalForm\`a\/\(1\ - \ r\)\)]], "." }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "2. Given the series ", Cell[BoxData[ FormBox[ RowBox[{ StyleBox[ SuperscriptBox[ RowBox[{ FormBox[\(\[Sum]\+\(n = 1\)\%\[Infinity]\ \((4\/3\)\), "TraditionalForm"], ")"}], "n"], FontWeight->"Bold"], " "}], TraditionalForm]]], " " }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[TextData[{ "\ta. ) Identify the first term ", StyleBox["a", FontSlant->"Italic"], " and the ratio ", StyleBox["r", FontSlant->"Italic"], "." }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell["\<\ \tb.) Do you think the infinite series converges or diverges? \ Why?\ \>", "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\tc.) Find the 20th partial sum ", Cell[BoxData[ \(TraditionalForm\`S\_20\)]], " and its decimal approximation to 15 significant digits", Cell[BoxData[ \(TraditionalForm\` . \)]] }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\td.) Find the 100th partial sum", Cell[BoxData[ \(TraditionalForm\`S\_100\)]], " and its decimal approximation to 15 significant digits." }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "3. Given the following series: ", StyleBox[" ", FontSize->18], StyleBox[" 1 - ", FontSize->24], Cell[BoxData[ \(TraditionalForm\`2\/3\)], FontSize->24], StyleBox[" + ", FontSize->24], Cell[BoxData[ \(TraditionalForm\`4\/\(\(9\)\(\ \)\)\)], FontSize->24], StyleBox["- ", FontSize->24], Cell[BoxData[ \(TraditionalForm\`8\/27\)], FontSize->24], StyleBox[" ", FontSize->24], StyleBox["+ . . .", FontSize->18] }], "Text", FontColor->RGBColor[1, 0, 0]], Cell["\ta. Write this infinite series using summation notation.", "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\t", StyleBox["b. Find the 10th partial sum, ", FontWeight->"Plain"], Cell[BoxData[ \(TraditionalForm\`S\_10\)], FontWeight->"Plain"], StyleBox[" and its decimal approximation.", FontWeight->"Plain"] }], "Text", FontFamily->"Helvetica", FontSize->14, FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ StyleBox["\tc. Find the 20th partial sum ", FontWeight->"Plain"], Cell[BoxData[ \(TraditionalForm\`S\_\(\(20\)\(\ \)\)\)], FontWeight->"Plain"], StyleBox["and its decimal approximation to 20 significant digits. ", FontWeight->"Plain"] }], "Text", FontFamily->"Helvetica", FontSize->14, FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[StyleBox["\td. At this point, what would you guess as the sum \ of the infinite series?", FontWeight->"Plain"]], "Text", FontFamily->"Helvetica", FontSize->14, FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ StyleBox["\te. Make a ListPlot of the partial sums ", FontWeight->"Plain"], Cell[BoxData[ \(TraditionalForm\`S\_n\)], FontWeight->"Plain"], StyleBox[" from n=1 to 50.", FontWeight->"Plain"] }], "Text", FontFamily->"Helvetica", FontSize->14, FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\t", StyleBox["f. Since this is a geometric series, identify ", FontWeight->"Plain"], StyleBox["a", FontWeight->"Plain", FontSlant->"Italic"], StyleBox[" and ", FontWeight->"Plain"], StyleBox["r", FontWeight->"Plain", FontSlant->"Italic"], StyleBox[". Use the formula for the sum of a convergent geometric series \ to find the sum of this series.", FontWeight->"Plain"] }], "Text", FontFamily->"Helvetica", FontSize->14, FontWeight->"Bold", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ StyleBox["4. Given the series ", FontSize->18], Cell[BoxData[ FormBox[ RowBox[{ StyleBox[ UnderoverscriptBox["\[Sum]", RowBox[{"n", StyleBox["=", FontSize->14], StyleBox["2", FontSize->14]}], "\[Infinity]"], FontSize->24], SuperscriptBox[ StyleBox[ RowBox[{ StyleBox["n", FontSize->24], "e"}]], \(-n\)]}], TraditionalForm]], FontSize->18] }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[TextData[{ "\ta. Use the Plot command to show that f(x) = ", Cell[BoxData[ FormBox[ SuperscriptBox[ StyleBox[ RowBox[{ StyleBox["x", FontSize->18], "e"}]], \(-x\)], TraditionalForm]]], "is a continuous, decreasing and positive function on the interval [2, \ 100]", StyleBox[".", FontWeight->"Bold"], " " }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell["\<\ \tb. Now use Integral Test to show whether or not the series \ converges. \ \>", "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\tc. Does the series ", Cell[BoxData[ FormBox[ RowBox[{ StyleBox[ UnderoverscriptBox["\[Sum]", RowBox[{"n", StyleBox["=", FontSize->14], StyleBox["2", FontSize->14]}], "\[Infinity]"], FontSize->24], SuperscriptBox[ StyleBox[ RowBox[{ StyleBox["n", FontSize->24], "e"}]], \(-n\)]}], TraditionalForm]]], "converge or diverge by the integral test?" }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\td. Compute the sum of the infinite series directly using ", StyleBox["Mathematica", FontSlant->"Italic"], ". " }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ StyleBox["5. Here's one that ", FontSize->18], StyleBox["Mathematica", FontSize->18, FontSlant->"Italic"], StyleBox[" can't handle very well: ", FontSize->18], Cell[BoxData[ FormBox[ StyleBox[\(\[Sum]\+\(n = 2\)\%\[Infinity] 1\/\((ln(n))\)\^n\), FontSize->24], TraditionalForm]], FontSize->18] }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[TextData[{ "\ta. ", StyleBox[" ", FontWeight->"Bold"], "Use the Plot command to show that f(x) = ", Cell[BoxData[ FormBox[ StyleBox[\(1\/\((ln(x))\)\^x\), FontSize->18], TraditionalForm]]], "is a continuous, decreasing and positive function on the interval [2, \ 100]", StyleBox[". ", FontWeight->"Bold"], " ", StyleBox["\n \n\tRemember , ", "MR"], StyleBox["ln(x)", "MR", FontSlant->"Italic"], StyleBox[" is input as ", "MR"], StyleBox["Log[x]", "MR", FontSlant->"Italic"], StyleBox[".", "MR"] }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\tb. Now use Integral Test to show whether or not the series converges.", StyleBox[" ", FontWeight->"Bold", FontColor->RGBColor[0, 0, 1]], " " }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\tc. Does the series ", Cell[BoxData[ FormBox[ StyleBox[\(\[Sum]\+\(n = 2\)\%\[Infinity] 1\/\((ln(n))\)\^n\), FontSize->24], TraditionalForm]]], "converge or diverge by the integral test?" }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ "\td. If you try to compute this series directly using ", StyleBox["Mathematica", FontSlant->"Italic"], ", it won't work. So instead, define a sequence of the partial sums and \ use ", StyleBox["ListPlot[Table[ ]]", "Input"], " to figure out what this series converges to." }], "Text", FontColor->RGBColor[1, 0, 0]], Cell[BoxData[ \(\[IndentingNewLine]\)], "Input"], Cell[TextData[{ StyleBox["Now that you're done, ", FontSize->18], "\n\t(1) \t", StyleBox["Clean up your work", FontWeight->"Bold"], " by deleting everything that's not needed. \n\t\tThere should only be the \ title, your names, section number, and the answers to your questions\n\t\t\ (with any needed explanations, graphs, etc.).\n\t(2) \tSave this to your \ disk.\n\t(3)\tGo back to Blackboard and upload your final lab report to the \ ", StyleBox["Digital Drop Box", FontWeight->"Bold"], ", located\n\t\tin the ", StyleBox["User Tools", FontWeight->"Bold"], " area. 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